9/(3x+5)=(45-27x)/(25-9x^2)

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Solution for 9/(3x+5)=(45-27x)/(25-9x^2) equation:


D( x )

3*x+5 = 0

25-(9*x^2) = 0

3*x+5 = 0

3*x+5 = 0

3*x+5 = 0 // - 5

3*x = -5 // : 3

x = -5/3

25-(9*x^2) = 0

25-(9*x^2) = 0

25-9*x^2 = 0

-9*x^2 = -25 // : -9

x^2 = 25/9

x^2 = 25/9 // ^ 1/2

abs(x) = 5/3

x = 5/3 or x = -5/3

x in (-oo:-5/3) U (-5/3:5/3) U (5/3:+oo)

9/(3*x+5) = (45-(27*x))/(25-(9*x^2)) // - (45-(27*x))/(25-(9*x^2))

9/(3*x+5)-((45-(27*x))/(25-(9*x^2))) = 0

9/(3*x+5)-((45-27*x)/(25-9*x^2)) = 0

9/(3*x+5)+(-1*(45-27*x))/(25-9*x^2) = 0

(9*(25-9*x^2))/((3*x+5)*(25-9*x^2))+(-1*(45-27*x)*(3*x+5))/((3*x+5)*(25-9*x^2)) = 0

9*(25-9*x^2)-1*(45-27*x)*(3*x+5) = 0

0 = 0

0/((3*x+5)*(25-9*x^2)) = 0

0/((3*x+5)*(25-9*x^2)) = 0 // * (3*x+5)*(25-9*x^2)

0 = 0

x belongs to the empty set

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